যদি rsinθ = 1, rcosθ = √3 হয়, তবে √3tanθ + 2 =?

প্রশ্ন: যদি rsinθ = 1, rcosθ = √3 হয়, তবে √3tanθ + 2 =?সমাধান:দেওয়া আছে,rsinθ = 1 ......... (1)rcosθ = √3 .............. (2)(1) ÷ (2) হতে পাইrsinθ/rcosθ = 1/√3বা, tanθ = 1/√3বা, √3√tanθ = 1এখন, √3tanθ + 2 = 1 + 2∴ √3tanθ + 3 = 3