(x/6) + (2/y) = 2, (x/4) - (1/y) = 1 হলে, (x, y)এর মান কত?

প্রশ্ন: (x/6) + (2/y) = 2, (x/4) - (1/y) = 1 হলে, (x, y)এর মান কত?

সমাধান:
(x/6) + (2/y) = 2..................(1)
(x/4) - (1/y) = 1 ...................(2)

(1) + (2) × 2 ⇒
(x/6) + (2/y) + (x/2) - (2/y) = 2 + 2
(x/6) + (x/2) = 4
(x + 3x)/6 = 4
4x/6 = 4
x/6 = 1
x = 6

(1) নং হতে পাই,
(x/6) + (2/y) = 2
(6/6) + (2/y) = 2
1 + (2/y) = 2
2/y = 1
y = 2

নির্ণেয় সমাধান (x, y) = (6, 2)