(x/2) + (y/3) = 3, x - (y/3) = 3 হলে, (x, y) = কত?

প্রশ্ন: (x/2) + (y/3) = 3, x - (y/3) = 3 হলে, (x, y) = কত?

সমাধান:
(x/2) + (y/3) = 3.............(1)
x - (y/3) = 3.............(2)

(1) + (2) ⇒
(x/2) + x = 3 + 3
(x + 2x)/2 = 6
3x/2 = 6
x/2 = 2
x = 4

(1) নং সমীকরণ থেকে পাই,
(4/2) + (y/3) = 3
2 + (y/3) = 3
y/3 = 3 - 2
y/3 = 1
y = 3

(x, y) =(4,3)