(x² - 5x + 6)/(x² - 9x + 20) এবং (x - 5)/(x - 3) এর গুণফল হলো-

প্রশ্ন: (x² - 5x + 6)/(x² - 9x + 20) এবং (x - 5)/(x - 3) এর গুণফল হলো-

সমাধান:
x² - 5x + 6 = x² - 2x -3x + 6
= x(x - 2) - 3(x - 2)
= (x - 2) (x - 3)
(x² - 9x + 20) =x² - 4x - 5x + 20
= x(x - 4) - 5(x - 4)
= (x - 4)(x - 5)

{(x² - 5x + 6)/(x² - 9x + 20)} × {(x - 5)/(x - 3)}
= {(x - 2) (x - 3)/(x - 4)(x - 5)}× {(x - 5)/(x - 3)}
= (x - 2)/(x - 4)