যদি x + 1/(x + 2) = 0 হয়, তাহলে x² + 1/x³ = কত?

x + 1/(x + 2) = 0
=> (x² + 2x + 1)/(x + 2) = 0
=> x² + 2x + 1 = 0
=> x² + 2.x.1 + 1² = 0
=> (x + 1)² = 0
=> x + 1 = 0
=> x = -1
তাহলে,
x² + 1/x³
= (-1)² + 1/(-1)³
= 1 + (-1)
= 1 - 1
= 0