Two trains start from stations A and B and travel towards each other at a speed of 50 kmph and 60 kmph respectively. A the time of their meeting, the second train had travelled 120 km more then the first. The distance between A and B is :

Question: Two trains start from stations A and B and travel towards each other at a speed of 50 kmph and 60 kmph respectively. A the time of their meeting, the second train had travelled 120 km more then the first. The distance between A and B is :

Solution:
At the time of meeting, let the distance travelled by the first train be x km.
Then, discount covered by the second train = (x + 120) km

ATQ,
x/50 = (x + 120)/60
⇒ 60x = 50(x + 120)
⇒ 60x - 50x = 6000
⇒ 10x = 6000
∴ x = 600

So, distance between A and B = (x + x + 120) km
= (600 + 600 + 120) km
= 1320 km