Two trains are moving in opposite directions at (50/3) m/s and 25 m/s. Their lengths are 1100 m and 900 m respectively. The time taken by the slower train to cross the faster train is:

Question: Two trains are moving in opposite directions at (50/3) m/s and 25 m/s. Their lengths are 1100 m and 900 m respectively. The time taken by the slower train to cross the faster train is:

Solution:
Relative speed = (50/3) + 25 m/s
= (50 + 75)/3 m/s
= 125/3 m/s

Distance covered = 1100 + 900 = 2000 m

Required time = (2000 × 3)/125 sec
= 48 sec