The sum of twice a number and three times of 42 is 238. What is the sum of thrice the number and two times of 42?

Question: The sum of twice a number and three times of 42 is 238. What is the sum of thrice the number and two times of 42?

Solution:
Let the number be 'p'

According to the question,
⇒ 2p + 3 × 42 = 238
⇒ 2p + 126 = 238
⇒ 2p = 112
⇒ p = 56

∴ Required sum:
= 3p + 2 × 42
= 3 × 56 + 2 × 42
=168 + 84
= 252