The sum of three consecutive odd natural numbers each divisible by 3 is 63. What is the smallest among them?

Question: The sum of three consecutive odd natural numbers each divisible by 3 is 63. What is the smallest among them?Solution: let, the numbers 3x, 3x + 6, 3x + 123x + 3x + 6 + 3x + 12 = 63⇒ 9x + 18 = 63 ⇒ 9x = 45∴ x = 5the smallest among them is = 3 × 5 = 15