The sum of L.C.M. and H.C.F. of two numbers is 1260. If their L.C.M. is 900 more than their H.C.F., find the product of two numbers.

Question: The sum of L.C.M. and H.C.F. of two numbers is 1260. If their L.C.M. is 900 more than their H.C.F., find the product of two numbers.

Solution:
Let the HCF be x

LCM = HCF + 900
LCM = x + 900 ...............(1)


And,
LCM + HCF = 1260
LCM + x = 1260 .................(2)

From (1) and (2) equation,
(x + 900) + x = 1260
⇒ 2x + 900 = 1260
⇒ 2x = 1260 - 900
⇒ 2x = 360
⇒ x = 360/2
⇒ x = 180

∴ HCF = 180

And, from equation (1),
LCM = HCF + 900
LCM = 180 + 900
∴ LCM = 1080

By formula, the product of the numbers is equal to the product of their HCF and LCM.

Product of numbers = HCF × LCM
= 180 × 1080
∴ Product = 194400