The product of the ages of A and B is 240. If twice the age of B is more than A’s age by 4 years, what was B’s age 2 years ago?

Question: The product of the ages of A and B is 240. If twice the age of B is more than A’s age by 4 years, what was B’s age 2 years ago?Solution: Let A’s present age be x years. Then, B’s present age = 240/x yearsSo, according to question2(240/x ) - x = 4⇒ 480 - x2 = 4x⇒ x2 + 4x - 480 = 0⇒ (x + 24) (x - 20) = 0⇒ x = 20B’s present age = 240/20 = 12 yearsThus, B’s age 2 years ago = 12 - 2 = 10 years