The maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils is =?

Question: The maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils is =?

Solution:
Required number of students
= HCF of 1001 and 910
= 91
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HCF of 1001 and 910:

We can find the HCF of 1001 and 910 using prime factorization.
First, let's find the prime factorization of both numbers:

1001 = 7 × 11 × 13
910 = 2 × 5 × 7 × 13

Now, to find the HCF, we take the product of the common prime factors with the lowest exponent:
The common prime factors are 7 and 13.

So, the product of the common prime factors is 7 × 13 = 91

Therefore, the HCF of 1001 and 910 is 91.