The distance between two stations is 240 km. When it strikes 5 pm in the clock, a train starts from each of these stations and travels towards the other one. They meet at a junction after 12 hrs. One of the trains is slower to the other one by 14km/hr. Find the speed of the slower train.

Let the speed of slower train = S km/hr
Speed of faster = (S + 14) km/hr
Trains meet after 12 hours.

Distance travelled by slower train in 12 hrs. = 12S
Distance travelled by faster train in 12 hrs. = 12(S + 14)

The total distance to be travelled between the two stations is given.
So, 12S + 12(S + 14) = 240
2S + 14 = 20
S = 3 km/hr.

Hence, The speed of the slower train is 3 km/hr.