The difference between two numbers is 3 and the difference between their squares is 39. What is the lowest number?

Question: The difference between two numbers is 3 and the difference between their squares is 39. What is the lowest number?Solution:Let the larger number is = aThen, the other number is = a - 3ATQ,a2 - (a - 3)2 = 39⇒ a2 - a2 + 6a - 9 = 39⇒ 6a = 39 + 9⇒ 6a = 48⇒ a = 48/6∴ a = 8∴ The lowest number is = 8 - 3 = 5