The average of two numbers x and y is 16. If x, y, z are non-negative integers such that x < z < y, what is the minimum possible average of x, y, z.

Question: The average of two numbers x and y is 16. If x, y, z are non-negative integers such that x < z < y, what is the minimum possible average of x, y, z.

Solution:
According to the questions,
(x + y)/2 = 16
x + y = 32
As x, y, z are non-negative integers and x < z < y.

The minimum possible value of these integers are,
X = 0
Z = 1
Y = 32

∴ Average = (0 + 32 + 1)/3
= 11