Statements: All green are blue. All blue are white.
Conclusions:
1. Some blue are green.
2. Some white are green.
3. Some green are not white.
4. All white are blue.

Question: Statements: All green are blue. All blue are white.

Conclusions:
1. Some blue are green.
2. Some white are green.
3. Some green are not white.
4. All white are blue.

Solution:
Statements:
All green are blue.
All blue are white.

From the statements, we get,
Green ⊂ Blue ⊂ White
This means every green object is blue, and every blue object is white. Therefore, every green object is also white.

Conclusion 1:
Some blue are green.
Since all green are blue, the green objects form a part of the blue group.

Therefore, at least some blue are green.
So, Conclusion 1 follows.

Conclusion 2:
Some white are green.
All green are blue, and all blue are white.
Hence, all green are also white.
Therefore, at least some white are green.

So, Conclusion 2 follows.

Conclusion 3:
Some green are not white.
From the statements, all green are blue and all blue are white.
So, every green object must be white.
Therefore, there cannot be any green object that is not white.

So, Conclusion 3 does not follow.

Conclusion 4:
All white are blue.
The statement says,
All blue are white.

But we cannot reverse the statement and say,
All white are blue.
There may be some white objects that are not blue.

So, Conclusion 4 does not follow.

Therefore, the correct answer is: Only (1) and (2) follow.