secA + tanA = 4/3, then find, secA - tanA = ?

Question: secA + tanA = 4/3, then find, secA - tanA = ?Solution:Given that,secA + tanA = 4/3We know,sec2A - tan2A = 1⇒ (secA + tanA)(secA - tanA) = 1⇒ (4/3)(secA - tanA) = 1⇒ (secA - tanA) = 1/(4/3)∴ secA - tanA = 3/4