Sabina got married 8 years ago. Today her age is 9/7 times her age at the time of her marriage. At present her daughter‘s age is one-sixth of her age. What was her daughter’s age 3 years ago?

Question: Sabina got married 8 years ago. Today, her age is 9/7 times her age at the time of her marriage. At present, her daughter's age is one-sixth of her age. What was her daughter's age 3 years ago?Solution:Let, Sabina's age 8 years ago be x years. Then, her present age = (x + 8) years.according to the question,x + 8 = (9/7) . x ⇒ 7x + 56 = 9x ⇒ 2x = 56 ⇒ x = 28∴ Sabina’s age now = (x + 8) years = (28 + 8) = 36 years.Her daughter’s age now = (1/6) × 36 years= 6 years.Her daughter’s age 3 years ago = (6 – 3) = 3 years.