Rahim and Shafiq are standing at two ends of a room with a width of 30 m. They start walking towards each other along the width of the room with a speed of 2 m/s and 1 m/s respectively. Find the total distance travelled by Rahim when he meets Shafiq for the third time.

When Rahim meets Shafiq for the third time,
they together would have covered a Distance of 5d, i.e 5 × 30m = 150 m.

The ratio of Speed of Rahim and Shafiq = 2 : 1,
so the total distance traveled by them will also be in the ratio 2 : 1
as the Time is taken is constant.

So the Distance traveled by Rahim will be (2/3) × 150= 100 m.