n is an integer chosen at random from the set (5, 7, 9, 11); p is chosen at random from the set {2, 6, 10, 14, 18}. What is the probability that n + p = 23?

Question: n is an integer chosen at random from the set {5, 7, 9, 11}; p is chosen at random from the set {2, 6, 10, 14, 18}. What is the probability that n + p = 23?

Solution:
Total number of possible pairs (n, p) = 4 × 5 = 20

Now find the pairs where n + p = 23:
If n = 5, then p = 18 → (5, 18) → 1 pair
If n = 7, then p = 16 (not in set)
If n = 9, then p = 14 → (9, 14) → 1 pair
If n = 11, then p = 12 (not in set)

So, favorable pairs = (5, 18) and (9, 14) → total 2 pairs.

∴ Probability = Favorable outcomes/Total outcomes
= 2/20 = 0.1

Therefore, the probability is 0.1.

Correct answer: ক) 0.1