log_ax = 1, log_ay = 2, log_az = 3 হলে log_a(x³y²/z) = ?

প্রশ্ন: log_ax = 1, log_ay = 2, log_az = 3 হলে log_a(x³y²/z) = ?

সমাধান:
log_a(x³y²/z)
= log_a(x³y²) - log_az [ log_aMN = log_aM - log_aN]
= log_ax³ + log_ay² - log_aZ
= 3log_ax + 2log_ay - log_aZ
= (3 × 1) + (2 × 2) - 3
= 4