loga√6 + loga√(2/3) = কত?

প্রশ্ন: loga√6 + loga√(2/3) = কত?সমাধান:loga√6 + loga√(2/3)= loga6(1/2) + loga(2/3)(1/2)= (1/2) loga6 + (1/2) loga(2/3)= (1/2) {loga6 + loga(2/3)}= (1/2) loga{6 × (2/3)}= (1/2) loga4= (1/2) loga22= (1/2) . 2 loga2= loga2