log₂√35 + log₂√(7/5) = ?

প্রশ্ন: log₂√35 + log₂√(7/5) = ?

সমাধান:
log₂√35 + log₂√(7/5)
= log₂(35)^1/2 + log₂(7/5)^1/2
= 1/2log₂(7 × 5) + 1/2log₂(7/5)
= 1/2[log₂(7 × 5) + log₂(7/5)]
= 1/2[log₂7 + log₂5 + (log₂7 - log₂5)]
= 1/2 × 2log₂7
= log₂7