log₂ √6 + log₂ √2/3 = কত?

প্রশ্ন: log₂ √6 + log₂ √2/3 = কত?

সমাধান:
log₂√6 + log₂√(2/3)
= log₂6(1/2) + log₂(2/3)^(1/2)
= (1/2) log₂6 + (1/2) log₂(2/3)
= (1/2) (log₂6 + log₂2/3)
= (1/2) log₂(6 × 2/3)
= (1/2) log₂4
= (1/2) log₂2²
= (1/2) . 2 log₂2
= log₂2
= 1