Let x be an integer which can take a value of 0 or 1. The statement if (x == 0) x =1 ; else x =0 ; is equivalent to which one of the following ?
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Let x be an integer which can take a value of 0 or 1. The statement <code>if (x == 0) x =1 ; else x =0 ;</code> is equivalent to which one of the following?
x = 1 + x;
x = x - 1;
x = 1 - x;
x = 1 % x;
The correct answer is: x = 1 - x;
To understand why the statement <code>x = 1 - x;</code> is equivalent to <code>if (x == 0) x = 1; else x = 0;</code>, consider the logical flow of the given if-else statement:
When <code>x == 0</code>: The statement <code>x = 1;</code> is executed.
When <code>x == 1</code>: The statement <code>x = 0;</code> is executed.
Now, let's analyze each choice to see which one replicates this behavior:
<code>x = 1 + x;</code> <br>This does the following:
If <code>x = 0</code>, then <code>x = 1 + 0 = 1</code>.
If <code>x = 1</code>, then <code>x = 1 + 1 = 2</code>.
Therefore, it does not correctly replicate the behavior of the given if-else statement.
<code>x = x - 1;</code> <br>This does the following:
If <code>x = 0</code>, then <code>x = 0 - 1 = -1</code>.
If <code>x = 1</code>, then <code>x = 1 - 1 = 0</code>.
Again, this does not correctly replicate the behavior because <code>x</code> can become -1, which is not a valid outcome based on the original problem constraints (i.e., <code>x</code> can only be 0 or 1).
<code>x = 1 - x;</code> <br>This does the following:
If <code>x = 0</code>, then <code>x = 1 - 0 = 1</code>.
If <code>x = 1</code>, then <code>x = 1 - 1 = 0</code>.
Hence, this choice perfectly replicates the behavior of the given if-else statement.
<code>x = 1 % x;</code> <br>This choice is problematic because it attempts to divide by zero when <code>x</code> is 0, which will result in a runtime error. Therefore, it is not a valid transformation of the given problem.
Therefore, upon examination of each choice, we conclude that the correct answer is: x = 1 - x;
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