In how many different ways can a committee of 3 members be selected from 5 people if a particular person must always be included in the committee?

Question: In how many different ways can a committee of 3 members be selected from 5 people if a particular person must always be included in the committee?

Solution:
Since one person must always be in the committee, we need to select the other two members from the remaining 4 people.
∴ Number of ways to choose the other two members = ⁴C₂
= (4 × 3)/(1 × 2)
= 6