In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11?

Question: In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11?

Solution:
In a simultaneous throw of two dice, we have n(S) = (6 × 6) = 36. (One dice can have 6 possibilites 1 - 6; similarly, Other dice will also have 6 possibilities)

Let E = event of getting a total of 10 or 11 = {(4, 6), (5, 5), (6, 4), (5, 6), (6, 5)}

∴ P(E) = n(E)/n(S) = 5/36