In a simultaneous throw of two coins, the probability of getting at least one head is-

Question: In a simultaneous throw of two coins, the probability of getting at least one head is-

Solution:
Here,
S = {HH, HT, TH, TT}

Let,
E = event of getting at least one head = {HT, TH, HH}

∴ P(E) = n(E)/n(S)
= 3/4