In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7.

Question: In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7.

Solution:
Here,
n(S) = (6 × 6) = 36

Let E = event of getting a total more than 7
= {(2, 6), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6), (5, 3), (5, 4), (5, 5), (5, 6), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

Therefore,P(E) = n(E)/n(S)
= 15/36
= 5/12