If x = 2y = 4z and xyz = 64, find the value of x.

Question: If x = 2y = 4z and xyz = 64, find the value of x. Solution:Given,x = 2y = 4zSo, y = x / 2 and z = x / 4 Now,xyz = 64⇒ x × (x/2) × (x/4) = 64⇒ x3/8 = 64⇒ x3 = 64 × 8 ⇒ x3 = 512⇒ x = ∛512∴ x = 8