If the size of a tile is 9" by 9", how many tiles are required to cover a 12 ft. wide and 18 ft. long floor?

Question: If the size of a tile is 9" by 9", how many tiles are required to cover a 12 ft. wide and 18 ft. long floor?Solution:Side of the tile is 9" = 9/12 ft.∴ Area of the tile is (9/12)2 = 81/144 sq. ft.Area of the floor = 12 × 18 = 216 sq. ft.Number of tiles = 216/(81/144) = (216 × 144)/81 = 384