If the product of three consecutive integers is 120, then the sum of the integers is:

Question: If the product of three consecutive integers is 120, then the sum of the integers is:

Solution:
120 = 2 × 2 × 2 × 3 × 5
= (2 × 2) × 5 × (2 × 3)
= 4 × 5 × 6

Clearly, the three consecutive integers whose product is 120 are 4, 5 and 6.

∴ Required sum
= 4 + 5 + 6
= 15