If the average of four consecutive odd integers is x, then in terms of x, which is the smallest among the following options?

Question: If the average of four consecutive odd integers is x, then in terms of x, which is the smallest among the following options?

Solution:
Let the four consecutive odd integers be represented by n, n + 2, n + 4, n + 6.
Their average is calculated by summing them and dividing by 4, which equals x.

Their average is,
x = {(n + (n + 2) + (n + 4) + (n + 6)}/4
⇒ x = (4n + 12)/4 = 4(n + 3)/4
⇒ x = n + 3
∴ n = x - 3

So the smallest integer in terms of (x - 3).