If secA + tanA = 5/2, what is the value of (secA - tanA)?

Question: If secA + tanA = 5/2, what is the value of (secA - tanA)?

Solution:
Given that
secA + tanA = 5/2
Or, 1/(secA + tanA) = 2/5
Or, (sec²A - tan²A)/(secA + tanA) = 2/5
Or, (secA + tanA)(secA - tanA)/(secA + tanA) = 2/5
∴ secA - tanA = 2/5