If (3/2)P = (5/7)Q = (6/5)R, then what is P : Q : R?

Question: If (3/2)P = (5/7)Q = (6/5)R, then what is P : Q : R?

Solution:
(3/2)P = (5/7)Q = (6/5)R .................(1)

LCM of their numerators = LCM of (3, 5, 6) = 30

Divide the eq. (1) by 30.
3P/(2 × 30) =5Q/(7 × 30) = 6R/(5 × 30)
⇒ P/20 = Q/42 = R/25

∴ P : Q : R = 20 : 42 : 25