2logx - log(2x - 1) = 0 হলে, x কত?

প্রশ্ন: 2logx - log(2x - 1) = 0 হলে, x কত?

সমাধান:
2logx - log(2x - 1) = 0
⇒ logx² - log(2x - 1) = 0
⇒ log{(x²/(2x - 1)} = 0
⇒ log{(x²/(2x - 1)} = log1  [ log1 = 0]
⇒ x²/(2x - 1) = 1
⇒ x² = 2x - 1
⇒ x² - 2x + 1 = 0
⇒ (x - 1)² = 0
⇒ x - 1 = 0
∴ x = 1