From two places, 60 km apart, M and N start towards each other at the same time and meet each other after 6 hour. If M traveled with 2/3 of his speed and N traveled with double of his speed, they would have met after 5 hours. The speed of M is-

Question: From two places, 60 km apart, M and N start towards each other at the same time and meet each other after 6 hour. If M traveled with 2/3 of his speed and N traveled with double of his speed, they would have met after 5 hours. The speed of M is-

Solution:
Let the speed of M = x kmph and the speed of N = y kmph

According to the question;
x × 6 + y × 6 = 60
x + y = 10 ............... (i)

And,
{(2x/3)×5} + (2y×5) = 60
(10x/3) + 10y = 60
10x + 30y = 180
x + 3y = 18 ...................... (ii)

From equation (i) × 3 - (ii)
3x + 3y - x - 3y = 30 - 18
Or, 2x = 12
x = 12/2
x = 6 kmph