From 50 L wine, 10 L is removed and replaced with water. Process repeated twice. Wine left = ?

Question: From 50 L wine, 10 L is removed and replaced with water. Process repeated twice. Wine left = ?

Solution:
A container has 50 liters of wine.
Each time, 10 liters of wine is removed and replaced with water.
This process is done twice.

After first removal of 10 L wine
Wine left = 40
Water added 10 L
Total 50 L
Wine part = 40/50= 4/5
Water part = 1/5
Now, again 10 liters of wine is removed
Wine removed = (4/5)×10 = 8
Water removed = (1/5) × 10 = 2

After removal:
Wine left = 40- 8 =32 L
Water left = 10- 2 = 8 L
10 L water added
New water = 18 L
and Wine Left = 32 L