Five siblings, born three years apart, have a combined age of 100 years. What is the age of the youngest one?

Question: Five siblings, born three years apart, have a combined age of 100 years. What is the age of the youngest one?Solution:Let the ages of siblings be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.Then,x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 100⇒ 5x = 100 - 30⇒ 5x = 70⇒ x = 14∴ Age of the youngest sibling = x = 14 years.