Find the square of a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

Question: Find the square of a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

Solution:
Let the number be x

Then, x + 17 = 60/x
⇒ x² + 17x − 60 = 0
⇒ x² + 20x − 3x − 60 = 0
⇒ (x + 20)(x − 3) = 0
∴ x = - 20, 3

The positive number = 3
Hence, the square of the positive number = 9