Find the smallest number of five digits exactly divisible by 16, 24, 36, and 54.

Question: Find the smallest number of five digits exactly divisible by 16, 24, 36, and 54.

Solution:
The smallest number of five digits is = 10000
The number must be divisible by the LCM of 16, 24, 36, and 54 = 432
On dividing 10000 by 432, we get 64 as the remainder.

So, required number is = 10000 + (432 - 64)
= 10000 + 368
= 10368