Find the product of two consecutive numbers where four times the first number is 10 more than thrice the second number.

Question: Find the product of two consecutive numbers where four times the first number is 10 more than thrice the second number.
Solution:
Let the numbers are ‘a' and ‘a + 1’.
According to the question :
4a = 3 × (a + 1) + 10
4a = 3a + 3 + 10
4a - 3a = 13
⇒ a = 13
Hence, the numbers are 13 and 14.

∴ Product = 13 × 14 = 182