Find the equation of the line with x-intercept = 3 and y-intercept = 4.

Question: Find the equation of the line with x-intercept = 3 and y-intercept = 4. Solution:Givenx-intercept = 3 (line passes through point (3, 0)y-intercept = 4 (line passes through point (0, 4) We know,The intercept form of a line is:x/a + y/b =1 ,where a = x-intercept and b = y-intercept.⇒ x/3 + y/4 = 1⇒ (4x + 3y)/12 =1⇒ 4x + 3y = 12 ⇒ 4x + 3y - 12 = 0 ∴ The equation of the line is 4x + 3y - 12 = 0