Find the area (in square cm) of a right angled triangle whose hypotenuse is 10 cm and base is 8 cm.

Question: Find the area (in square cm) of a right angled triangle whose hypotenuse is 10 cm and base is 8 cm

Solution:
Given that,
Hypotenuse = 10 cm
Base = 8 cm

Let height = h

By Pythagoras theorem,
h² + 8² = 10²
⇒ h² = 100 - 64
⇒ h² = 36 = 6²
∴ h = 6

We know,
Area of triangle = (1/2) × Base × Height
= (1/2) × 8 × 6
= 24 sq.cm