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Consider the following recursive function fun (s , y). what is the value of fun ( 4, 3) int fun ( int x , int y) if ( x =0) return y; return fun ( x,1, x+y); |

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13

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<h1>Explanation of Recursive Function</h1>

Let us consider the given recursive function <code>fun(x, y)</code>. The function is defined as follows:

<pre><code> int fun(int x, int y) { if (x == 0) return y; return fun(x - 1, x + y); } </code></pre>

We need to compute the value of <code>fun(4, 3)</code>. Let's break it down step by step:

<h2>Step-by-Step Breakdown</h2>
  1. We start by calling <code>fun(4, 3)</code>.

  2. Since <code>x</code> is not 0 (it is 4), we proceed to the recursive call <code>fun(3, 4+3)</code>.

  3. Thus, the next call is <code>fun(3, 7)</code>.

  4. Again, <code>x</code> is not 0 (it is 3), we proceed to the recursive call <code>fun(2, 3+7)</code>.

  5. Thus, the next call is <code>fun(2, 10)</code>.

  6. Continuing, <code>x</code> is still not 0 (it is 2), we move to the recursive call <code>fun(1, 2+10)</code>.

  7. Thus, the next call is <code>fun(1, 12)</code>.

  8. Yet again, <code>x</code> is not 0 (it is 1), we proceed to the recursive call <code>fun(0, 1+12)</code>.

  9. Thus, the final call is <code>fun(0, 13)</code>.

  10. Now, <code>x</code> equals 0, which means we hit our base case. We return <code>y</code>, which is 13.

Therefore, the value of <code>fun(4, 3)</code> is 13.

<h2>The Correct Answer</h2>

The correct answer is 13. Let's verify why the other options are not correct:

  • 9: This would be incorrect, as it does not follow the pattern of the recursive additions.

  • 10: This would be incorrect, as it also does not match the computed value.

  • 12: This does not meet the final sum produced by the recursion steps.

<h2>Conclusion</h2>

By thoroughly examining each step of the recursive function, we confirm that the value of <code>fun(4, 3)</code> is indeed 13. This manner of breaking down the steps not only helps in understanding the process but also reinforces the concepts of recursion and base cases in programming.

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