B is twice the age of C, and A is 2 years older than B. With their ages adding up to 42, what is A's age?

Question: B is twice the age of C, and A is 2 years older than B. With their ages adding up to 42, what is A's age?Solution: Let,C is = x years oldB is 2x years oldA is (2x + 2) years oldNow,2x + 2x + 2 + x = 42⇒ 5x + 2 = 42⇒ 5x = 40∴ x = 8A is (2 × 8) + 2 years old= 16 + 2 years old= 18 years old