∠B is the right angle of a right angles triangle ABC. If tanA = 3/4, then 5sinACosA =?

Question: ∠B is the right angle of a right angles triangle ABC. If tanA = 3/4, then 5sinACosA = ?

Solution:

দেওয়া আছে,
tanA = 3/4

∴ অতিভুজ = √(3² + 4²) = √(9 + 16) = 5

∴ sinA = AB/AC = 3/5
cosA = BC/AC = 4/5

∴ 5sinACosA = 5 × (3/5) × (4/5)
= 12/5