Asif got married 8 years ago. Today his age is 9/7 times his age at the time of his marriage. At present his daughter's age, is one-sixth of his age. What was his daughter's age 3 years ago?

Question: Asif got married 8 years ago. Today his age is 9/7 times his age at the time of his marriage. At present his daughter's age, is one-sixth of his age. What was his daughter's age 3 years ago?

Solution:
Let, Asif's age 8 years ago be x years.
Then, his present age (x + 8) years.

ATQ,
x + 8 = 9x/7
⇒ 9x = 7x + 56
⇒ 9x - 7x = 56
⇒ 2x = 56
∴ x = 28

Asif's age now = x + 8 = 28 + 8 = 36 years.
His daughter's age now = 36/6 = 6 years.
His daughter's age 3 years ago = (6 - 3) = 3 years.