An observer who is 1.8 meters tall is standing 20 meters away from a tower. If the angle of elevation from his eye to the top of the tower is 45°, what is the height of the tower?

Question: An observer who is 1.8 meters tall is standing 20 meters away from a tower. If the angle of elevation from his eye to the top of the tower is 45°, what is the height of the tower?

Solution:

পর্যবেক্ষকের উচ্চতা, CD = 1.8 মিটার
এখানে, CD = EB
টাওয়ারের উচ্চতা = AB

এখন,
tan∠C = AE/CE
⇒ tan45° = AE/20
⇒ 1 = AE/20
∴ AE = 20

∴ AB = AE + BE
= 20 + 1.8
= 21.8 m

∴ টাওয়ারটির উচ্চতা 21.8 meters.