Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age?

Question: Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age?

Solution:
Let the age of an younger person be A
age of elder person = (A + 16)

According to the question, we have
3(A - 6) = (A + 16 - 6)
⇒ 3A - 18 = A + 10
⇒ 2A = 28
⇒ A = 14

∴ The younger and elder person age is 14 years old and 30 years old.